(I3
I94
I8
(dp0
Vtaxi.%l
p1
(Vtaxi.cpp
p2
S'#include<iostream>\r\n#include<iomanip>\r\n#include<cmath>\r\n#include<cstring>\r\nusing namespace std;\r\nint main ()\r\n{\r\n    int n,km[100000],lv[100000],k,a[100000],br=0,kr=0;\r\n    cin>>n;\r\n    for (int i=0;i<n;i++)\r\n    {\r\n        cin>>km[i];\r\n    }\r\n    for (int i=0;i<n;i++)\r\n    {\r\n        cin>>lv[i];\r\n    }\r\n    cin>>k;\r\n    for (int i=0;i<k;i++)\r\n    {\r\n        cin>>a[i];\r\n        br++;\r\n    }\r\n    for (int i=0;i<br;i++)\r\n    {\r\n        km[i]=0;\r\n    }\r\n    for (int i=n-1;i>=0;i--)\r\n    {\r\n        for (int j=0;j<i;j++)\r\n        {\r\n            if (km[j]<km[j+1]) swap(km[j],km[j+1]);\r\n        }\r\n    }\r\n\r\n    for (int i=n-1;i>=0;i--)\r\n    {\r\n        for (int j=0;j<i;j++)\r\n        {\r\n            if (lv[j]>lv[j+1]) swap(lv[j],lv[j+1]);\r\n        }\r\n    }\r\n    for (int i=0;i<n;i++)\r\n    {\r\n        if (km[i]==0) break;\r\n        kr=kr+km[i]*lv[i];\r\n    }\r\n    cout<<kr<<"\\n";\r\n    return 0;\r\n}\r\n/*\r\n5\r\n2 5 3 6 4\r\n5 2 1 5 5\r\n2\r\n1 2\r\n*/\r\n'
p3
tp4
stp5
.